I’m trying to solve this problem.
I read the editorial. But i don’t understand, how did they come up with the number 27, i mean how can we arrive to a conclusion that
Since m ≤ 10^8 by the constraints, for n ≥ 27 the answer is always equal to m .
I’m trying to solve this problem.
I read the editorial. But i don’t understand, how did they come up with the number 27, i mean how can we arrive to a conclusion that
Since m ≤ 10^8 by the constraints, for n ≥ 27 the answer is always equal to m .
For n>=27, 2n, will be greater than 10^8. also,
(small_number)%(definetely greater than small) = small_number itself.
To arrive at the conclusion, they think of what power of 2 will exceed m for sure no matter what the m be.
I hope it solves your query.
To arrive at the conclusion, they think of what power of 2 will exceed m for sure no matter what the m be.
Thankyou.