while( ch >= ‘0’ && ch <= ‘9’ )

n = (n<<3)+(n<<1) + ch-‘0’,ch=getcx();

#define getcx getchar //this has been defined at the beginning

Can someone please explain to me what does the above code mean ? Specifically, I dont understand n<<3 , n<<1 .

while( ch >= ‘0’ && ch <= ‘9’ )

n = (n<<3)+(n<<1) + ch-‘0’,ch=getcx();

#define getcx getchar //this has been defined at the beginning

Can someone please explain to me what does the above code mean ? Specifically, I dont understand n<<3 , n<<1 .

k<<l is the same as k*2^l ( ^ is power ).

k>>l is the same as k/2^l (integer dividing : 3/2=1, 100/99 = 0)

It is called bitwise shift.

Examples :

1<<2 = 1 * 2^2 = 1 * 4 = 4

1<<3 = 1 * 2^3 = 1 * 8 = 8

3<<4 = 3 * 2^4 = 3 * 16 = 48

3>>4 = 3/2^4 = 3/16 = 0

It is called shift, beacuse every time you shift binary representation of number by one.

Ex.: (in binary)

a = 10010001

a<<1 = 100100010

a<<2 = 1001000100

a<<3 = 10010001000

…

a = 10010001

a>>1 = 1001000

a>>2 = 100100

a>>3 = 10010

a>>4 = 1001

a>>5 = 100

a>>6 = 10

a>>7 = 1

a>>8 = 0

…

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All clear . Thanks a lot.

n=(n<<3)+(n<<1)+ch-‘0’ =(n.2^3)+(n.2^1)+ch-‘0’=n.(8+2)+ch-‘0’=10n +ch-‘0’