Ceil A-B ,What's wrong with my code ?

//It’s the code for Ceil A-B problem in practice set

#include<stdio.h>

int main()
{
    unsigned long a=0;
    unsigned long b=0;
        scanf("%lu %lu", &a, &b);
        printf("%lu

“,(a-b));
printf(”%lu
", (a-b)^1);
return 0;
}

You should not output the first line i.e. remove printf("%lu
",(a-b)) .

1 Like

#include<stdio.h>

int main()
{
    unsigned long a=0;
    unsigned long b=0;
        scanf("%lu %lu", &a, &b);
        printf("%lu

", (a-b)^1);
return 0;
}

Again wrong…
What can i do ?
My way of implementation is correct ?

When a-b = 1 your answer will be zero , but it has leading zeroes . So it is giving WA .
Here is your corrected code .

# include < stdio.h>
int main()
{
    unsigned long a=0;
    unsigned long b=0;
    unsigned long ans=0;
    scanf("%lu %lu", &a, &b);
    ans=(a-b)^1;
    if (ans==0)
        ans=2;
    printf("%lu

",ans); return 0;
}

1 Like

remove printf("%lu
",(a-b)^1);
because we can not write ^

Thanks. I forgot that fact. Now ok. Once again thank you.