CLSI C++ Easy Explanation

general
1

Approach:
We need to check whether IQ N is at least 10 times the difficulty B.

If N >= 10*B print YES otherwise print NO.

Code:

#include <bits/stdc++.h>
using namespace std;

int main() {
    int n,b;
    cin >> n >> b;

    if(n >= 10*b)
        cout << "YES";
    else
        cout << "NO";
}

Time Complexity:
O(1)