Tester: Harris Leung

432

None

# PROBLEM:

Chef is shopping for masks. In the shop, he encounters 2 types of masks:

• Disposable Masks — cost X but last only 1 day.
• Cloth Masks — cost Y but last 10 days.

Chef wants to buy masks to last him 100 days. He will buy the masks which cost him the least. In case there is a tie in terms of cost, Chef will be eco-friendly and choose the cloth masks. Which type of mask will Chef choose?

# EXPLANATION:

For 100 days, Chef will require \frac{100}{1} = 100 disposable masks or \frac{100}{10} = 10 cloth masks.
Therefore if 100 \cdot X \lt 10 \cdot Y, Chef will buy Disposable masks, otherwise he will buy Cloth masks.

# SOLUTIONS:

Setter's Solution
#include <bits/stdc++.h>
using namespace std;
int main()
{
int test_cases;
cin>>test_cases;

for(int tc = 1 ; tc <= test_cases ; tc++)
{
int disposable_price , cloth_price;
cin>>disposable_price>>cloth_price;

if((100 * disposable_price) < (10 * cloth_price))
cout<<"Disposable"<<endl;
else
cout<<"Cloth"<<endl;
}

return 0;
}