How can we break something which is already broken ??? 

Codechef : kaisa lage mera majak
Server is already Broken 
They are visible now lol
problem is not visible ?? it’s again server issue!!!
Completely Waste of scheduling my time.

Now Its Visible
Well I submitted a solution with a 10^10 loop and it still gave me a correct answer. Here is my code ACQOdk - Online C++ Compiler & Debugging Tool - Ideone.com .
I am wondering is this some kind of compiler optimisation because even ideone compiles it within a sec but I get a segmentation fault in my local system.
Contest over. It was really nice. One doubt: Was the last problem suitable for Div3?
Yes I think it was just a trivial binary lifting, wasn’t it ?
The time limit for this was 20 seconds, what’s so strange about it?
How did you solve E , wasnt it meant to be solved using LCA?
Nice contest, but only 1961 people participated as compared to 10,985 in January Lunchtime.
yeah it was, prefix sums+ lca
I think 1-4 were very easy and (just an opinion) suddenly 5 was hard. It was lowest common ancestor, which is hard to implement…
I think using endl instead of “\n” is screwing up the things. They specifically mentioned to use fast IO
