PROBLEM LINK:
Author: Adarsh Kumar Sinha
DIFFICULTY:
Easy
SOLUTION:
Setter's Solution
/*----- || Hare Krishna || -----*/
/* "WHY DO WE FALL, BRUCE?" */
//#pragma GCC optimize("Ofast")
//#pragma GCC target("avx,avx2,fma")
#include<bits/stdc++.h>
#define ll long long
#define endl '\n'
#define elif else if
#define pb push_back
#define pf push_front
#define PI 3.1415926535897932384
#define MOD 1000000007
using namespace std;
char alpha[26] = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
string s;
int t;
int main(){
ios_base::sync_with_stdio(false);
cin.tie(NULL);
// freopen("input5.txt","r",stdin);
// freopen("output5.txt","w",stdout);
t=1;
while(t--){
int n,m,a,b;
cin >> n;
cin >> m;
int mat[n+1][n+1];
memset(mat, 0 ,sizeof(mat)); // pre-setting as 0
while(m--){
int a,b;
cin >> a >> b;
mat[a][b]=1; // indicating there's a route between a and b
mat[b][a]=1; // same
}
vector<int> rdx(n+1, 0); // to store how many cities are directly enrouted with current city
for(int i=1; i<=n; i++){
for(int j=1; j<=n; j++){
if(mat[i][j]==1 && i!=j){ // not considering self connecting roads as it will not add new city for its spread
rdx[i]++;
}
}
}
int ans=0;
for(int i=1; i<=n; i++){
int cities= 1+rdx[i]; // cities covered if the curent city is chosen as the hot-spot
ans = max(ans, cities);
}
cout << ans << endl;
}
}