# CP00 Editorial

Difficulty

Easy

Solution

We have one rectangle of dimension a\times b and another of dimension c\times d. To obtain a square by vertically stacking these two, their lengths must be equal (a = c) and the sum of their widths must be equal to their lengths (b + d = a = c). To obtain a square by horizontally stacking the rectangles, their widths must be equal (b = d) and the sum of their lengths must be equal to their widths (a + c = b = d).

Code

#include<bits/stdc++.h>
using namespace std;
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int T;
cin>>T;
while(T--)
{
int a,b,c,d;
cin>>a>>b>>c>>d;
if(a==c && (b+d)==a)
cout<<"Yes\n";
else if(b==d && (a+c)==b)
cout<<"Yes\n";
else
cout<<"No\n";
}
return 0;

}