# cpp output

Can anyone explain how to print output in CPP in the following way:
if the answer is 11, it should print 11.0, but if the answer is the square root of 3, it should print 1.732051 and so on…
I mean how to change the decimal point depending on the answer. I have tried setprecision but it doesn’t seem to help.

If you know how many decimal places you need to output you can add `fixed` after `setprecision(x)`

x = 6;
cout << setprecision(x) << fixed << sqrt(3) << endl;

Had i been there, I would have tried something on lines of-

Let root have the answer we have t print.

``````int q =root; //integral part of answer
if ( q*q == OriginalNumber)
print upto 1 decimal using "printf ("%.1lf",root);"
else
print upto 6 deciamls (or the number of decimals needed, acc to Q) (again, by "printf ("%.6lf", ans);"
``````

From what I am able to grasp from the Q, if the ans is integer like 10, 11, 12 etc then we just have to add 1 decimal, and if its not an integral value, like 1.7324… then 6 decimals.

(Note- The above method is true if Q states that the number [whose square root we have to find] is strictly an integer.)

The Q is ambiguous/needs clarification for cases where the number given is of form 25.6 x 25.6 or 28.71 x 28.71 (meaning will the ans be of form 28.710 or 28.710000)

EDIT-If this is some Q you came across, can you provide the link?

@ayush933 Suppose you know upto how many decimal places you want the answer(ans) and let that be ‘t’
then write the answer as printf("%.tf",ans)
Eg. you know that you want answer upto 6 decimal places write it as printf("%.6f",ans).Hope you got this.

See my code below

``````#include<bits/stdc++.h>
using namespace std;

int main()
{
float ans=11;
if( ans == 11)
{
cout << setprecision(1) <<fixed << ans;
}
else
{
ans=sqrt(3.0);
cout<< setprecision(6) << fixed << ans;
}

}
``````

Click on there to know more about ‘setprecision’ and ‘fixed’

I hope you will get this simpler and easy code.

I used 11 and square root of 3 just as an example.
There are numeral test cases, answers to which I don’t know.
How to do it there?

Yes if the ans is an integer then only one decimal point but if its not an integer then not exactly 6 decimal point.
In that case, the number of decimal points would depend on answer itself
like the answer would 28.710 and not 28.710000.

1 Like

Just change this code according to the requirement otherwise tell me the whole question in proper format so that i will provide you full and clear cut explanation.

Okayy. I see. If the number can be a decimal, then we cannot use “q*q == OriginalNumber” since “==” operator should not be used to compare 2 floats (Errors come in way).

For 28.71 case, one important thing to know is that this means that the inputted number is not an integer. (a decimal number x decimal number = a decimal number.)

hmm…thinking on this I can only think of a naïve implementation atm. Can you quote the question? That would help.