Here is the link to the problem:

I have been trying to solve this problem from quite a while now. I have understood the logic behind it i.e, to find the first most significant bit that is set in R and not in L and just make all the bits with lower significance than this bit set in the final answer. The previous bits including this found-bit will be the same in the answer that is same in both L and R given to us.

I would really appreciate if someone could let me know where I am going wrong.

Here is my code:

```
/*Priyansh Agarwal*/
#include<bits/stdc++.h>
using namespace std;
#define fastio() ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL)
#define nline "\n"
typedef long long ll;
typedef unsigned long long ull;
int main()
{
fastio();
#ifndef ONLINE_JUDGE
freopen("Input.txt","r",stdin);
freopen("Output.txt","w",stdout);
#endif
int t;
cin>>t;
while(t--)
{
ull a,b;
cin>>a>>b; // a means L and b means R
ull ans=0;
int p=log2(b); //finding the number of bits in the bigger number
for(int i=p;i>=0;i--)
{
if((b & ull(pow(2,i)))>=1)
{
ans = ans | ull(pow(2,i)); //making that bit set in the answer which is set in the bigger number
if((a & ull(pow(2,i)))==0) //checking if this bit is set in L also or not
{
ans = ans | ull((pow(2,i)-1)); //making all the bits smaller than this set in the final answer
break; //breaking as we dont need to check any further
}
}
}
cout<<ans<<endl;
}
return 0;
}
```