# PROBLEM LINK:

Practice

Contest: Division 1

Contest: Division 2

Contest: Division 3

Contest: Division 4

* Author:* yash_daga

*jay_1048576*

**Tester:***iceknight1093*

**Editorialist:**# DIFFICULTY:

789

# PREREQUISITES:

None

# PROBLEM:

Alice and Bob roll 3 regular 6-sided dice each, and obtain values A_1, A_2, A_3 and B_1, B_2, B_3, respectively.

A player’s score is the sum of the maximum two values they obtain.

Find out who has a larger score.

# EXPLANATION:

Let A denote Alice’s score, and B denote Bob’s score.

They can be found as follows:

A = A_1 + A_2 + A_3 - \min(A_1, A_2, A_3) \\
B = B_1 + B_2 + B_3 - \min(B_1, B_2, B_3)

The idea here is that to find the sum of the largest two values, we can instead take the sum of all three values, then remove the smallest one.

Once A and B are found, compare them using an `if`

condition and print `Alice`

, `Bob`

, or `Tie`

appropriately.

# TIME COMPLEXITY

\mathcal{O}(1) per testcase.

# CODE:

## Editorialist's code (Python)

```
for _ in range(int(input())):
a1, a2, a3, b1, b2, b3 = map(int, input().split())
alice, bob = a1+a2+a3 - min(a1, a2, a3), b1+b2+b3 - min(b1, b2, b3)
print('Alice' if alice > bob else ('Bob' if alice < bob else 'Tie'))
```