Difference in outputs. Why?

help
1

Given below is a C code:
#include<stdio.h>
int main()
{int t;
scanf("%d",&t);
while(t–)
{int y,m,d;
scanf("%d:%d:%d",&y,&m,&d);
if(m==4||m==6||m==9||m==11)
printf("%d\n",(61-d)/2+1);
else if(m==2)
{if(y%400==0||(y%100!=0&&y%4==0))
printf("%d\n",(29-d)/2+1);
else
printf("%d\n",(59-d)/2+1);
}
else
printf("%d\n",(31-d)/2+1);
}
return 0;
}

And given below is a C++14 code:
#include<bits/stdc++.h>
using namespace std;
int main()
{ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int T;
cin>>T;
while(T–)
{int y,m,d;
scanf("%d:%d:%d",&y,&m,&d);
if(m==4||m==6||m==9||m==11)
cout<<(61-d)/2+1<<"\n";
else if(m==2)
{if(y%400==0||(y%100!=0&&y%4==0))
cout<<(29-d)/2+1<<"\n";
else
cout<<(59-d)/2+1<<"\n";
}
else
cout<<(31-d)/2+1<<"\n";
}
return 0;
}

Now why does the C code produce correct output and the C++ code not even though they practically follow the same logic. In fact the only difference between these two code segments is that they are written in different languages.

2

Please format your code - the C++ code at least is uncompilable.

In spite of that, I can at least make a guess - you are mixing C-style input (scanf) with C++ -style input (cin), but are using ios_base::sync_with_stdio(false); so they are not synchronised and conflict with one another.

Edit:

Also, what input do they give different output for?

3

I don’t know. I was getting wrong answer in the C++ code and Correct in the C code. Anyway, thanks. You were right.

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