MY Approach

First, find out the n-k minimum elements from the array and remove them then find the median of the remaining elements which would be our maximum median.

```
int n, k;
cin >> n >> k;
vector<int> org(n);
vector<pair<int, int>> dup(n);
// duplicate array for storing the numbers with their indexes
for (int i = 0; i < n; i++)
{
cin >> org[i];
dup[i].first = org[i];
dup[i].second = i;
}
// sorting the duplicate array
sort(dup.begin(), dup.end());
// finding the first n-k elements of the duplicate array in the original array and making them as -1,as they do not contribute to our required sequence
for (int i = 0; i < (n - k); i++)
org[dup[i].second] = -1;
// printing the middle element in the duplicate vector,excluding the n-k elements
cout << dup[(n - k) + k / 2].first << endl;
// printing the elements of the orginal array whose value is not set -1
for (int i = 0; i < n; i++)
{
if (org[i] != -1)
cout << org[i] << " ";
}
```

this is my code ,does anyone say why does not work.