Problem Statement:
Given a positive integer c, determine whether it can be expressed as the sum of two square numbers. In other words, you need to determine if there exist two non-negative integers a and b such that: c = a^2 + b^2
Approach:
This problem can be solved using a two-pointer technique. The idea is based on the observation that if c = a^2 + b^2, then a and b must satisfy the equation for some values between 0 and the square root of c.
Detailed Approach:
-
Two-Pointer Technique:
- Initialize two pointers:
leftstarts at0(corresponding toa).rightstarts atsqrt(c)(corresponding tob).
- The goal is to find if there exists a pair
(a, b)such thata^2 + b^2 = c.
- Initialize two pointers:
-
Iterative Search:
- Calculate the sum
sum = left^2 + right^2. - Compare
sumwithc:- If
sum == c, returntruebecause we have found the valuesaandb. - If
sum < c, increment theleftpointer to increase the sum. - If
sum > c, decrement therightpointer to decrease the sum.
- If
- Continue this process until
leftexceedsright.
- Calculate the sum
-
Return Result:
- If no such pair is found by the time
leftexceedsright, returnfalse.
- If no such pair is found by the time
Complexity:
- Time Complexity: The time complexity of this solution is
O(sqrt(c)). This is because the maximum number of iterations is determined by the value ofsqrt(c), as both pointers move towards each other. - Space Complexity: The space complexity is
O(1), as the solution only uses a few extra variables for computation.
Note:
There are other approaches too to solve this problem. Can you think think of any?