Problem Statement:
Given a positive integer c
, determine whether it can be expressed as the sum of two square numbers. In other words, you need to determine if there exist two non-negative integers a
and b
such that: c = a^2 + b^2
Approach:
This problem can be solved using a two-pointer technique. The idea is based on the observation that if c = a^2 + b^2
, then a
and b
must satisfy the equation for some values between 0
and the square root of c
.
Detailed Approach:
-
Two-Pointer Technique:
- Initialize two pointers:
left
starts at0
(corresponding toa
).right
starts atsqrt(c)
(corresponding tob
).
- The goal is to find if there exists a pair
(a, b)
such thata^2 + b^2 = c
.
- Initialize two pointers:
-
Iterative Search:
- Calculate the sum
sum = left^2 + right^2
. - Compare
sum
withc
:- If
sum == c
, returntrue
because we have found the valuesa
andb
. - If
sum < c
, increment theleft
pointer to increase the sum. - If
sum > c
, decrement theright
pointer to decrease the sum.
- If
- Continue this process until
left
exceedsright
.
- Calculate the sum
-
Return Result:
- If no such pair is found by the time
left
exceedsright
, returnfalse
.
- If no such pair is found by the time
Complexity:
- Time Complexity: The time complexity of this solution is
O(sqrt(c))
. This is because the maximum number of iterations is determined by the value ofsqrt(c)
, as both pointers move towards each other. - Space Complexity: The space complexity is
O(1)
, as the solution only uses a few extra variables for computation.
Note:
There are other approaches too to solve this problem. Can you think think of any?