# Editorial-Game of Maths |Encoding Junior November 21

Author: Srinjoy Pal
Tester: Abhisekh Paul ,Sayan Poddar
Editorialist: Srinjoy Pal

CAKEWALK

# PREREQUISITES:

Basic Math , Basic data types

# PROBLEM:

Take a character and an integer as input and perform required operations and print the output after each query.

# EXPLANATION:

After taking each query check the character part .
‘S’ subtract the number
‘D’ divide the number
‘M’ multiply the number

# SOLUTION:

Setter’s Solution
C++

``````#include <bits/stdc++.h>
using namespace std;
int main(){
long long int t;
cin>>t;
while(t--)
{
long long int n,r;
cin>>n>>r;
while(r--)
{
char c;
long long int m;
cin>>c;
if(c=='A')
{
cin>>m;
n+=m;
}
else if (c=='S')
{
cin>>m;
n-=m;
}
else if (c=='M')
{
cin>>m;
n*=m;
}
else if (c=='D')
{
cin>>m;
n=n/m;
}
cout<<n<<endl;
}
}
return 0;
}
``````

Tester’s Solution
Python

``````for _ in range(int(input())):
a=[int(i) for i in input().split()]
c=a[0]
for _ in range(a[1]):
b=[i for i in input().split()]
if b[0]=="A":
c+=int(b[1])
print(c)
elif b[0]=="S":
c-=int(b[1])
print(c)
elif b[0]=="M":
c*=int(b[1])
print(c)
elif b[0]=="D":
c/=int(b[1])
c=int(c)
print(int(c))
``````

Tester’s Solution
Java

``````//package myplace;
import java.util.Scanner;
class ecjnov {
public static void  main (String[] args) {
Scanner sc=new Scanner(System.in);
int t=Integer.parseInt(sc.nextLine());
while(t>0)
{
String s[]=sc.nextLine().split(" ");
int n=Integer.parseInt(s[0]);
int r=Integer.parseInt(s[1]);
for(int i=0;i<r;i++)
{
String s1[]=sc.nextLine().split(" ");
String c=s1[0];
int m=Integer.parseInt(s1[1]);
if(c.equals("A"))
n=m+n;
else if(c.equals("S"))
n=n-m;
else if(c.equals("M"))
n=m*n;
else
n=n/m;
System.out.println(n);
}

t--;
}
}}``````
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