Editorial - PIN

editorial
,
1

Problem link : The Michael Scott Paper Company
Difficulty : Medium
Setter : Harshit Garg

Code :

#include <bits/stdc++.h>
using namespace std;
string S;
int N, cnt;
int main()
{
    cin >> N >> S;
    for (int i = 0; i < 1000; i++)
    {
        int c[3] = {i / 100, (i / 10) % 10, i % 10};
        int f = 0;
        for (int j = 0; j < N; j++)
        {
            if (S[j] == ('0' + c[f]))
                f++;
            if (f == 3)
                break;
        }
        if (f == 3)
            cnt++;
    }
    cout << cnt << endl;
    return 0;
}
1 Like
2

great explaination

3

Thanks @real_bheem :slight_smile: