# PROBLEM LINK:

* Author:* Shubham_Goswami

*Abhijeet Trigunait*

**Tester:***Shubham Goswami*

**Editorialist:**# DIFFICULTY:

CAKEWALK

# PREREQUISITES:

Array

# PROBLEM:

Chef asks Chefina for a date . But Chef is a hardworking guy and has a value for money so he already pre-planned about his date and fixed a budget to spend from his savings .

Given a fixed budget B and an array A[ ] of size N for the amount of N expenses .

You have to calculate the total amount and check whether the date costs him beyond his fixed budget . If the total amount goes beyond budget then print “YES” otherwise “NO” .

# EXPLANATION:

Given an array with n amounts of expenses and a fixed budget , so you have to check whether the total array sum goes beyond the fixed budget or not . If the total array sum goes beyond the budget you have to print “YES”, else print “NO” . If you don’t want to use array no issue , just keep on summing the amounts while taking input .

# SOLUTIONS:

## Setter's Solution

```
/*
Author- Shubham Goswami
*/
#include<bits/stdc++.h>
#define lli long long int
using namespace std;
int main()
{
int T; // This is for testcases (T)
cin>>T;
while(T--){ // T times the loop will take input N,B .
lli N,B,i,temp,sum=0;
cin>>N>>B;
for(i=0;i<N;i++){ // Taking N inputs (the amounts, chef spent on date)
cin>>temp;
sum+=temp; // calculating the total amount spent by chef
}
if(sum>B){ // Checking if the total amount spent(sum) goes beyond the budget(b)
cout<<"YES\n";
}
else{
cout<<"NO\n";
}
}
return 0;
}
```