#include <iostream>
using namespace std;
int main() {int t;
cin>>t;
while(t--)
{int n;int a[200]={0};int k=0;
cin>>n;
char str[n];
cin>>str;
for(int i=0;i<n;i++)
{int c=(int)str[i];
a[c]++;}
for(int i=97;i<=122;i++)
{if(a[i]%2!=0)
k=-1;break;
}
if(k==-1)
cout<<"NO"<<endl;
else
cout<<"YES"<<endl;
}
// your code goes here
return 0;
}
WHY AM I GETTING A WRONG ANSWE HERE?
It’s better to provide the submission link!
There are no braces in the if block so the break; statement always runs in the first iteration of the loop…
1 Like
i dont know about the question but this seems to your error if you dont give braces then if condition only checks the k-- but never break so.
{
if(a[i]%2!=0)
{
k=-1;break;
}
}
maybe this solves your error.
1 Like
but once k is assigned value -1 then the absence of break statement doesnt matter as well. if once k is assigned -1 then we’ll have NO printed