How can I find if an integer X is between integer A and B by using bit-wise operators?

We need to determine A < X < B then,

- A-X < 0
- B-X > 0

```
#include<stdio.h>
#define CHAR_BIT 8
int main()
{
int a,b,x,amx,bmx,sign_amx,sign_bmx;
scanf("%d %d %d",&a,&b,&x);
amx=a-x;
bmx=b-x;
if(!bmx) // If B-X = 0 then make bmx negative
bmx=-1; // to exclude upper limit
sign_amx = 0 | (amx >> (sizeof(int) * CHAR_BIT - 1)); // if amx<0 then sign_amx is -1 else 0
sign_bmx = 0 | (bmx >> (sizeof(int) * CHAR_BIT - 1)); // if bmx<0 then sign_amx is -1 else 0
if(sign_amx && !sign_bmx)
printf("Yes!!");
else
printf("No!!");
return 0;
}
```

[Alternate]We need to determine A < X < B then,

- A-X < 0
- B-X > 0

```
#include<stdio.h>
#define CHAR_BIT 8
int main()
{
int a,b,x,amx,bmx,sign;
scanf("%d %d %d",&a,&b,&x);
amx=a-x;
bmx=b-x;
if(!bmx) // If B-X = 0 then make bmx negative
bmx=-1; // to exclude upper limit
sign = 0 | ((amx^bmx) >> (sizeof(int) * CHAR_BIT - 1));
if(sign)
printf("Yes!!");
else
printf("No!!");
return 0;
}
```

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why would you do so ?

Can we use arithmetic operators(+,-)??