PROBLEM LINK:
Practice
Contest: Division 1
Contest: Division 2
Contest: Division 3
Contest: Division 4
Authors: naisheel, jalp1428
Tester: tabr
Editorialist: iceknight1093
DIFFICULTY:
716
PREREQUISITES:
None
PROBLEM:
There are N buns. A family of 5 needs X buns each daily, and can survive for D days after the buns run out.
Find the number of days they can survive for.
EXPLANATION:
There are 5 people, each needing X buns.
This is a total of 5X buns each day.
N buns will thus last for \displaystyle\left\lfloor \frac{N}{5X} \right\rfloor days, where \left\lfloor \ \right\rfloor denotes the floor function.
Adding in the extra D days, we see that the final answer is
\left\lfloor \frac{N}{5X} \right\rfloor + D
TIME COMPLEXITY
\mathcal{O}(1) per testcase.
CODE:
Editorialist's code (Python)
for _ in range(int(input())):
n, x, d = map(int, input().split())
print(n//(5*x) + d)