# PROBLEM LINK:

Practice

Contest: Division 1

Contest: Division 2

Contest: Division 3

Contest: Division 4

* Author:* notsoloud

*jay_1048576*

**Tester:***iceknight1093*

**Editorialist:**# DIFFICULTY:

713

# PREREQUISITES:

None

# PROBLEM:

Ordering food online costs N rupees but comes with a 10\% discount, while dining at the restaurant costs M rupees.

Which is the cheaper option?

# EXPLANATION:

To truly compare the costs, we need to compute the actual cost of ordering online, after the discount is applied.

Since, the discount is of 10\%, the cost of ordering online is N - \frac{N}{10} = \frac{9N}{10}

So,

- If \frac{9N}{10} \lt M, ordering online is cheaper.
- If \frac{9N}{10} \gt M, dining is cheaper.
- If \frac{9N}{10} = M, either one is fine.

The constraints are small so doing floating-point computations should get you AC.

However, if you wish to work purely with integers, you can compare the values of 9N and 10M.

# TIME COMPLEXITY

\mathcal{O}(1) per test case.

# CODE:

## Editorialist's code (Python)

```
for _ in range(int(input())):
n, m = map(int, input().split())
x, y = 9*n, 10*m
if x < y: print('Online')
elif x > y: print('Dining')
else: print('Anyone')
```