GFRIEND - EDITORIAL

editorial
,
1

PROBLEM LINK:

Contest

Setter: debrc

Tester: dustu_947 , mishra_roshan

Editorialist: debrc

DIFFICULTY:

Cakewalk

PREREQUISITES:

Basic observations.

PROBLEM:

Given a Username S ending with F for Female and M for Male, you have to determine whether that string belongs to Male Username or Female Username. Print ‘Yes’ if its a Female Username or else ‘No’.

EXPLANATION

You only have to check the last character of a Username. If it’s F print ‘Yes’ as it’s a Female User.
If it’s M print ‘No’ as it’s a Male User.

TIME COMPLEXITY

Time complexity is O(1) to check the last character of a string.

SOLUTIONS:

Setter's Solution
C++ 
#include <iostream>
using namespace std;

int main() {
    int t;
    cin>>t;
    while(t--){
        string s;
        cin>>s;
        if(s[s.size()-1]=='F')
        {
            cout<<"Yes"<<endl;
        }
        else 
        {
            cout<<"No"<<endl;
        }
    }
	return 0;
}
Python 
for _ in range(int(input())):
    s = input()
    if s[len(s) - 1] == 'F':
        print('Yes')
    else:
        print('No')
Tester's Solution 
#include <iostream>
#include<stdio.h>
#include<string.h>
using namespace std;

int main() {
	// your code goes here
	int T;
	std::cin >> T;
	while(T--)
	{
	    int l;
	    char Uname[1000000];
	    scanf("%s",Uname);
	    l=strlen(Uname);
	    if(Uname[l-1]=='F')
	        std::cout << "Yes" << std::endl;
	    else
	        std::cout << "No" << std::endl;
	}
	return 0;
}

Feel free to Share your approach.
Suggestions are welcomed as always had been