Guys please look at this this problem :)

general
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1

I need to solve this question for large inputs for which I’m currently getting the wrong answer.

check the question, guys.

Happy codding people!

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In which lang?

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cpp14

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Share your submission link

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It is working in python but not in c++ or java

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unsigned long long stores garbage value for a number of range 10^36.
Have a Look

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Python and Java have the ability to store such big numbers. Use BigInteger in Java.

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I got AC using C++14

C++14 AC Solution using Boost Library

Boost has data types in multiprecision library for types ranging from 128 to 1024 bits.

Source: Stack Overflow

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https://www.codechef.com/viewsolution/34659471
my submission link .

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with BigInteger it is easy .
but I was looking for c++ solution but thanks.

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yes it is showing TLE in 2nd input

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Thank you so much ! :smiley:

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Is boost available by default in c++ ? I though you have to download it locally to use boost… Which wont be possible for online judges…

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Boost is available on CC but most of the sites don’t support it eg- CF

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Yeah, that’s the procedure. Fortunately, in Codechef BOOST library is supported. If the library is not supported, you can use __int128 type to store 128 bit numbers. But there is a workaround to get input and display the number using >> and << operators. You have to overload it to support this datatype.

I found one for printing it: Printing __int128 variable in C++

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I think the intended solution for this is to store the numbers as strings, and use a string multiplication algorithm like karatsuba multiplication.

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Simple multiplication will work for the given constraints. As 100! has around 150 digits but given constraint has only 36 digits

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Thanks for the information sebastian.
Won’t use this method there.
BigInteger it is :smiley:

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That’s right. But we have to take the input for the given 36 digit number right? And it won’t fit in a long long datatype.

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Yeah I meant that you can simply do string multiplication with O(n*m) time comp. You don’t need Karatsuba Multiplication algo here

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