It might be very basic for many but I don’t know what’s happening here. Any help from the community of genius is much appreciated 
!
C++ Code :
double a = (log(243))/(log(3));
float b = ((log(243))/(log(3)));
cout<<a<<"\n";
cout<<b<<"\n";
cout<<floor(a)<<"\n";
cout<<floor(b)<<"\n";
Output :
5
5
4
5
Why the float is given as integer there in the output.
It got floored in division.
Just the standard lack of floating-point precision 
Try the following small alteration:
#include <iostream>
#include <cmath>
#include <limits>
#include <iomanip>
using namespace std;
int main()
{
double a = (log(243))/(log(3));
float b = ((log(243))/(log(3)));
cout << std::setprecision(std::numeric_limits<long double>::digits10 + 1) << a <<"\n";
cout << std::setprecision(std::numeric_limits<long double>::digits10 + 1) << b << "\n";
cout << floor(a) << "\n";
cout << floor(b) << "\n";
}
[simon@simon-laptop][19:56:41]
[~/devel/hackerrank/otherpeoples]>./a.out
4.999999999999999112
5
4
5
Thanks
Wooooh… 