Help me in solving AOCP10 problem

help
,
1

My issue

My code

// Update the code below to solve the problem

#include <stdio.h>

int main() {
    int t;
    scanf("%d", &t);
    for (int i = 0; i < t; i++) {
        int n,p,q;
        scanf("%d", &n);
        int A[n];
        int count;
        for (int j = 0; j < n; j++) {
            scanf("%d", &A[j]);
        }
       
        for(int i=0;i<n;i++)
        {
            if(A[i]==(6*(i+1)+i))
            {
                p=p-1;
            }
            else if(A[i]==7*i)
            {
                q=q-1;
            }
            else
            {
                p=4;
                q=4;
            }
        
        }
        count=n+p+q;
        
        
    printf("%d\n",count);
    }
}

Learning course: C for problem solving - 2
Problem Link: CodeChef: Practical coding for everyone

2

@soyelrana
In the given problem, we have to find if a holiday falls on either Sunday or Saturday and print the total number of holidays.

The logic I used here was like this;

We already have at least 8 holidays in the month. Now,

While taking A[j] as input, I am checking if it falls on a saturday or sunday. If it is equals to either [ 6,13, 20,27 ]* or [7,14,21,28], if yes, we continue in the loop, otherwise, the count of holidays is increased by +1.

Finally, we print number of holidays, denoted here by c.

You can refer to the following code to get a better understanding.

// Update the code below to solve the problem

#include <stdio.h>

int main() {
    int t;
    scanf("%d", &t);
    for (int i = 0; i < t; i++) {
        int n,c=8;
        scanf("%d", &n);
        int A[n];
        for (int j = 0; j < n; j++) {
            scanf("%d", &A[j]);
            if( (A[j]==6)||(A[j]==13)||(A[j]==20)||(A[j]==27)||(A[j]==7)||(A[j]==14)||(A[j]==21)||(A[j]==28) )
            {
                continue;
            }
            else
            {
                c++;
            }
        }
        printf("%d\n",c);
    }
}