Help me in solving AOCV215 problem

help
,
1

My issue

include <bits/stdc++.h>
using namespace std;

int main()
{
int t;
cin >> t;

while(t--)
{
    int N;
    int product=1;
    cin >> N;
    int A[N];
    for(int i = 0; i < N; i++)
    {
        cin >> A[i];
    }
    for(int i=0;i<N;i++){
    product=product*A[i];
    }
    if(product<0){
        cout<<"1"<<endl;
    }
    else if(product>=0)
    {
        cout<<"0"<<endl;
    }
   
}
return 0;

}
this is my code can you guys help me find out the error

My code

// this code has some logical error - debug this code to solve the problem

#include <bits/stdc++.h>
using namespace std;

int main() 
{
	int t;
    cin >> t;
	
	while(t--)
	{
	    int N;
	    int product=1;
	    cin >> N;
	    int A[N];
	    for(int i = 0; i < N; i++)
	    {
	        cin >> A[i];
	    }
	    for(int i=0;i<N;i++){
	    product=product*A[i];
	    }
	    if(product<0){
	        cout<<"1"<<endl;
	    }
	    else if(product>=0)
	    {
	        cout<<"0"<<endl;
	    }
       
	}
	return 0;
}

Learning course: C++ for problem solving - 2
Problem Link: CodeChef: Practical coding for everyone

2

@priyaranjan11
Your logic is not right.
u can do it like this

// Solution as follows

#include <bits/stdc++.h>
using namespace std;

int main() 
{
	int t;
    cin >> t;
	
	while(t--)
	{
	    int N;
	    cin >> N;
	    int A[N];
	    for(int i = 0; i < N; i++)
	    {
	        cin >> A[i];
	    }
	    int count_neg = 0;
        int count_zero = 0;
        for(int i = 0; i < N; i++)
        {
            if(A[i] == 0)
            {
                count_zero++;
            }
            else if(A[i] < 0)
            {
                count_neg++;
            } 
        }
        // The condition to check the count of zeros was missing
        if((count_zero > 0) || (count_neg%2 == 0))
        {
            cout << 0 << endl;
        }
        // The condition where count_neg is odd was missing
        else
        {
            cout << 1 << endl;
        }
	}
}