Help me in solving BMCCP06 problem

help
,
1

My issue

please explain the conditional statement put in line 13 and 14

My code

// Update the '_' in the code below to solve the problem

#include <stdio.h>

int main() {
    int t;
    scanf("%d", &t);
    for (int i = 0; i < t; i++) {
        int A, B;
        scanf("%d %d", &A, &B);

        // Declare variables for lower and higher of the 2 numbers
        int minAB = A < B ? A : B;
        int maxAB = A > B ? A : B;
        int flag = 0;

        while (minAB <= maxAB) {
            // Condition is met, hence set flag = 1
            if (minAB == maxAB) {
                flag = 1;
                break;
            }
            else {
                // Update the minimum value as per the problem statement
                minAB *= 2;
            }
        }

        if (flag == 1) {
            printf("YES\n");
        }
        else {
            printf("NO\n");
        }
    }
    return 0;
}

Learning course: Beginner DSA in C
Problem Link: CodeChef: Practical coding for everyone

2

Here what we have used is called a “ternary operator”.
Basically it is something like this -
( (condition) ? (expression_A) : (expression_B) )
So if the “condition” becomes true then the whole thing is replaced by “expression_A”, otherwise it is replaced by “expression_B”
By whole thing I mean everything inside the outer parentheses.
So when we write-

int minAB = A < B ? A : B;

it means check if A < B. If so, then entire right hand side becomes A (expression_A in our example), basically value of A gets assigned to minAB. If condition (A<B) is false the same thing happens with B.