Help me in solving BMMC20 problem

My issue

My code

// Update the code below to solve the problem

#include <iostream>
#include <string>
using namespace std;

int main() 
{
 int t;
 cin>>t;
while(t--)
 { 
   int X,Y;
   cin>>X>>Y;
   if(3*X==2*Y)
   cout<<X<<endl;
 if(3*X>2*Y)
 cout<<X<<endl;
 if(3*X<2*Y)
 cout<<Y<<endl;
  }
 return 0;
}

Learning course: Solve Programming problems using C++
Problem Link: CodeChef: Practical coding for everyone

@sinhasadhana95
U have to print the smaller cost value
i have corrected it in your code hope u will get it.

#include <iostream>
#include <string>
using namespace std;

int main() 
{
 int t;
 cin>>t;
while(t--)
 { 
   int X,Y;
   cin>>X>>Y;
   if(3*X==2*Y)
   cout<<3*X<<endl;
 if(3*X>2*Y)
 cout<<2*Y<<endl;
 if(3*X<2*Y)
 cout<<3*X<<endl;
  }
 return 0;
}

They have asked to print the total cost. But you just print the cost of one room. You got the logic right but just the printing part (Also check a simpler solution below)

#include <iostream>
#include <string>
using namespace std;

int main() 
{
    int t;
    cin >> t;
    while(t--)
    { 
        int X, Y;
        cin >> X >> Y;
        if(3 * X == 2 * Y)
            cout << 3 * X << "\n"; // or can also print 2 * Y
        else if (3 * X < 2 * Y)
            cout << 3 * X << "\n";
        else
            cout << 2 * Y << "\n";
    }
    return 0;
}

You can also do it in one line. They asked to print the minimum cost of the rooms. So you just need the minimum of 3* X and 2 * Y. So you can simply do it this way.

#include <iostream>
#include <string>
using namespace std;

int main() 
{
    int t;
    cin >> t;
    while(t--)
    { 
        int X, Y;
        cin >> X >> Y;
        cout << min(3 * X, 2 * Y) << "\n";
    }
    return 0;
}