# Help me in solving CLEARDAY problem

### My issue

Chef classifies a day to be either rainy, cloudy, or clear.

In a particular week, Chef finds

X days to be rainy and

Y days to be cloudy.
Find the number of clear days in the week.

Input Format
The first and only line of input will contain two space-separated integers

X and

Y, denoting the number of rainy and cloudy days in the week.
Output Format
Output the number of clear days in the week.

# Constraints 0 ≤ � , � ≤ 7 0≤X,Y≤7 0 ≤ � + � ≤ 7 0≤X+Y≤7 Sample 1: Input Output 2 3 2 Explanation: There are 7 7 days in a week. If there are 2 2 rainy days and 3 3 cloudy days, then the remaining 7 − 2 − 3

2
7−2−3=2 days are clear.

# Sample 2: Input Output 3 4 0 Explanation: If there are 3 3 rainy days and 4 4 cloudy days, then the remaining 7 − 3 − 4

0
7−3−4=0 days are clear.

### My code

``````#include <stdio.h>

int main
{
if 0<=3 , 2<=7

return 0;
}

``````

Problem Link: CLEARDAY Problem - CodeChef

include
using namespace std;

int main() {