### My issue

Chef classifies a day to be either rainy, cloudy, or clear.

In a particular week, Chef finds

�

X days to be rainy and

�

Y days to be cloudy.

Find the number of clear days in the week.

Input Format

The first and only line of input will contain two space-separated integers

�

X and

�

Y, denoting the number of rainy and cloudy days in the week.

Output Format

Output the number of clear days in the week.

# Constraints

0

≤

�

,

�

≤

7

0≤X,Y≤7

0

≤

�

+

�

≤

7

0≤X+Y≤7

Sample 1:

Input

Output

2 3

2

Explanation:

There are

7

7 days in a week. If there are

2

2 rainy days and

3

3 cloudy days, then the remaining

7

−

2

−

3

2

7−2−3=2 days are clear.

# Sample 2:

Input

Output

3 4

0

Explanation:

If there are

3

3 rainy days and

4

4 cloudy days, then the remaining

7

−

3

−

4

0

7−3−4=0 days are clear.

### My code

```
#include <stdio.h>
int main
{
if 0<=3 , 2<=7
return 0;
}
```

Problem Link: CLEARDAY Problem - CodeChef