Help me in solving DOREWARD problem

help
,
1

My issue

My code

#include <iostream>
using namespace std;

int main() {
int n,a;
cin>>n;
for(int i =0;i<n;i++){
    cin>>a;
    if(a<=3){
        cout<<"BRONZE"<<endl;
    }if(3<a>=6){
        cout<<"SILVER"<<endl;
    }if(a>6){
        cout<<"GOLD"<<endl;
    }
}
	return 0;
}

Problem Link: DOREWARD Problem - CodeChef

2

@uday_yenke

You have written the second if condition incorrectly.

Instead of writing it like;

if(3<a>=6)

It should have been like;

if((a>3)&&(a<=6)) // if number is either 4, 5 or 6.

You have to separate the conditions and join them via a relational operator in case of having multiple constraints to consider.

Here is my code for reference.

# cook your dish here
for _ in range(int(input())):
    x=int(input())
    if(x<=3):
        print('BRONZE')
    elif(x<=6):
        print('SILVER')
    else:
        print('GOLD')