Help me in solving EZSPEAK problem

help
,
1

My issue

My code

#include <iostream>
#include<stdlib.h>
using namespace std;

int main() {
	int i,t;
	cin>>t;
	
	for(i=0; i<t; i++){
	    int n,j;
	    cin>>n;
	    
	    string S[n];
	    cin>>S;
	    
	    int c=0;
	    
	    for(j=0; j<n; j++){
	        if(S[j]=='a' || S[j]=='e' || S[j]=='i' || S[j]=='o' || S[j]=='u'){
	            c=0;
	            continue;
	        }
	        else if(c<4){
	            c++;
	        }
	        else if(c==4){
	            cout<<"YES"<<endl;
	            break;
	        }
	    }
	    cout<<"NO"<<endl;
	}
	return 0;
}

Problem Link: EZSPEAK Problem - CodeChef

2

@divyanshusinha
There is a flaw in the logic here. In the loop, checking for vowel and resetting the counter , otherwise increment the counter and break when threshold is reached.

Check counter value and print output.

NOTE: Code is in Python but logic will be same.

for i in range(n):
        if(s[i]=='a'):  c=0
        elif(s[i]=='e'): c=0
        elif(s[i]=='i'): c=0
        elif(s[i]=='o'): c=0
        elif(s[i]=='u'): c=0
        else:   c+=1
        
        if(c==4):
            break
    if(c==4):
        print('no')
    else:
        print('yes')

Something like this, where we check if (c==4) and break from for loop.

Then we verify if value of c==4 or not, as it is possible that program might complete the loop without c ever reaching the value of 4.

If c==4 is true, we print NO. Otherwise, print YES.