Help me in solving EZSPEAK problem

help
1

My issue

Why my soln is wrong if it is successfully executing against given input

for t in range(int(input())):
n = int(input())
s = input()
v = [‘a’,‘e’,‘i’,‘o’,‘u’]
f = ‘’
for l in s:
if l not in v:
f += l
elif l in v:
break
if len(f) >= 4:
print(‘NO’)
else:
print(‘YES’)

My code

# cook your dish here
for t in range(int(input())):
    n = int(input())
    s = input()
    v = ['a','e','i','o','u']
    f = ''
    for l in s:
        if l not in v:
            f += l
        elif l in v:
            break
    if len(f) >= 4:
        print('NO')
    else:
        print('YES')

Problem Link: EZSPEAK Problem - CodeChef

2

@deverath_1
U have made implementation mistake
i have corrected it in your code ,hope u will get it.

# cook your dish here
for t in range(int(input())):
    n = int(input())
    s = input()
    v = ['a','e','i','o','u']
    f = 0
    for l in s:
        if l not in v:
            f += 1
        elif l in v:
            if f>=4:
                break
            else:
                f=0
    if f >= 4:
        print('NO')
    else:
        print('YES')
1 Like
3

// your code goes here
Scanner read=new Scanner(System.in);
int t=read.nextInt();
for(int i=0;i<t;i++){
int n=read.nextInt();
String s=read.next();
int c=0;
for(int j=0;j<n;j++){
if(s.charAt(j)!=‘a’ && s.charAt(j)!=‘e’ && s.charAt(j)!=‘i’ && s.charAt(j)!=‘o’ && s.charAt(j)!=‘u’){
c++;
}
else{
c=0;
}
if(c>=4){
System.out.println(“NO”);
break;
}
}
if(c!=4){
System.out.println(“YES”);
}