Help me in solving EZSPEAK problem

help
,
1

My issue

count=0
for i in range(int(input())):
n = int(input())
s = input().lower()
k=[‘a’,‘e’,‘i’,‘o’,‘u’]
for i in s:
if i not in k:
count=count+1
else:
count=count
if count>4:
print(‘NO’)
else:
print(‘YES’)
count=0

i am getting correct output but i get status wrong

My code

count=0
for i in range(int(input())):
    n = int(input())
    s = input().lower()
    k=['a','e','i','o','u']
    for i in s:
        if i not in k:
            count=count+1
        else:
            count=count
    if count>4:
        print('NO')
    else:
        print('YES')
    count=0

Problem Link: EZSPEAK Problem - CodeChef

2

4 or more consonants should be present consecutively, where as your code is checking for consonants which are non-consecutive also.