# Help me in solving FIFTYPE problem

### My code

``````# cook your dish here
x=int(input())
for i in range(0,x):
count=0
a=int(input())
if(a%2!=0):
c=a-3
count+=1
while(c>50):
c-=3
count+=1
d=50-c
r=d//2
print(r+count)
elif(a==50):
print("0")
else:
if(a<50):
p=50-a
print(p//2)
else:
while(a>50):
a-=3
count+=1
d=50-a
r=d//2
print(r+count)

``````

Problem Link: FIFTYPE Problem - CodeChef

@pragathi40
The logic I used here was like this;

We need the level to be 50. Charging increases the level by +2, while using reduces the level by -3.

I took a while loop with the termination condition being battery level reaching 50%. There can be three different cases here;

• Case 1: Battery at 50% already. No charge or usage required, zero as output.

• Case 2: Battery lower than 50%, we keep charging until it’s equals to or more than 50%.

• Case 3: Battery more than 50%, we keep using the device until it’s less than or equals to 50%

You can take a look at the following code for a better understanding.

``````#include <stdio.h>

int main(void)
{
int t,n;
scanf("%d",&t);
while(t--)
{
scanf("%d",&n);
int q=0;
while(n!=50)
{
if(n>50)
{
n=n-3;
q++;
}
else
{
n=n+2;
q++;
}
}
printf("%d\n",q);
}

return 0;
}

``````