### My issue

### My code

```
# cook your dish here
```

Problem Link: GDTURN Problem - CodeChef

@arnab003jn369

Here, the question is providing us with two values, namely **x** and **y**, denoting the number obtained after rolling a dice.

A dice has 6 faces having 6 distinct values *(1,2,3,4,5,6)*. We need to find if the sum of (**x+y**) is greater than *6* or not.

```
# cook your dish here
for i in range(int(input())):
x,y=map(int,input().split())
if((x+y)>6):
print('yes')
else:
print('no')
```

Here, the question asked us to check whether the addition of two numbers is more than 6 or not?

If it is more than 6 than it should return “YES” and if it is not than it should return “NO”.

Here is the sample code for you -

```
#include <iostream>
using namespace std;
int main()
{
int t,x,y;
cin >> t;
for(int i = 0; i < t; i++){
cin >> x >> y;
if(x+y > 6){
cout << "YES" << endl;
}
else{
cout << "NO" << endl;
}
}
return 0;
}
```

Hope this will help you.

include <stdio.h>

int main(void) {

// your code goes here

int t,x,y,i,sum;

scanf(“%d”,&t);

```
for( i=0;i<t;i++)
{
scanf("%d %d",&x,&y);
sum=x+y;
if(sum >6)
{
printf("YES\n");
}
else
{
printf("NO\n");
}
```

}

return 0;

}

In this program they have asked to see whether the sum of the dices is greater than 6.I have used t denoting the number of test case. I have taken x, y variables as the numbers on the dices, then I have used sum variable to add both the values then in if condition I have compared whether the sum is greater than 6 or not .If the sum is greater than 6 then yes is the answer otherwise no is the answer.