Help me in solving GDTURN problem

help
,
1

My issue

My code

# cook your dish here

Problem Link: GDTURN Problem - CodeChef

2

@arnab003jn369
Here, the question is providing us with two values, namely x and y, denoting the number obtained after rolling a dice.

A dice has 6 faces having 6 distinct values (1,2,3,4,5,6). We need to find if the sum of (x+y) is greater than 6 or not.

# cook your dish here
for i in range(int(input())):
    x,y=map(int,input().split())
    if((x+y)>6):
        print('yes')
    else:
        print('no')
3

Here, the question asked us to check whether the addition of two numbers is more than 6 or not?
If it is more than 6 than it should return “YES” and if it is not than it should return “NO”.
Here is the sample code for you -

#include <iostream>

using namespace std;

int main()
{
    int t,x,y;
    cin >> t;
    for(int i = 0; i < t; i++){
        cin >> x >> y;
        if(x+y > 6){
            cout << "YES" << endl;
        }
        else{
            cout << "NO" << endl;
        }
    }
    return 0;
}

Hope this will help you. :blush:

4

include <stdio.h>

int main(void) {
// your code goes here
int t,x,y,i,sum;
scanf(“%d”,&t);

for( i=0;i<t;i++)
{
    scanf("%d %d",&x,&y);
    sum=x+y;

    if(sum >6)
    {
        printf("YES\n");
    }
    else
    {
        printf("NO\n");
    }

}
return 0;
}

In this program they have asked to see whether the sum of the dices is greater than 6.I have used t denoting the number of test case. I have taken x, y variables as the numbers on the dices, then I have used sum variable to add both the values then in if condition I have compared whether the sum is greater than 6 or not .If the sum is greater than 6 then yes is the answer otherwise no is the answer.