What to do if get run time error
# cook your dish here
# cook your dish here
import math
t=int(input())
while(t!=0):
n=int(input())
temp=10**(n-1)
temp1=10**n
for i in range(temp,temp1):
if(i%3==0 and i%9!=0 and i%2!=0):
print(i)
break
t-=1
Learning course: Jump from 2* to 3*
Problem Link: Make it Divisible Practice Problem in Jump from 2* to 3* - CodeChef
@koushal10
loop through such a big number will give to tle .
There is another very interesting logic to it.
we n=know that a number divisible by 9 will always be divisible by 3 .
so the logic is print n-1 times 9 and one time 3.
refer my c++ code
#include <iostream>
using namespace std;
int main() {
// your code goes here
int t;
cin>>t;
while(t--)
{
int n;
cin>>n;
for(int i=0;i<n-1;i++)
cout<<9;
cout<<3;
cout<<endl;
}
return 0;
}