# Help me in solving MXEVNSUB problem

### My issue

my issue is that why is my solution wrong, i saw other’s solutions and they just did a-1 in the 2nd case, meanwhile i did a-2.
example:-
if input is 2. then output should be 0, why? since then only we get an even sum. The solution given by others gives 1 as output, but it gives a odd sum bro.
another example:-
if input is 6, then output should be 4, why? since then we get an even sum. the solution given by others will give 5 as output, but it gives a odd sum ;-; .

pls explain what am i doing wrong???

### My code

``````#include <iostream>
using namespace std;

int main() {
int t;
cin >> t;
while(t--){
int a;
cin >> a;
if (((a+3)%4)==0){
cout<<a-1;
}
else if (((a+2)%4)==0){
cout << a-2;
}
else{
cout<<a;
}
cout << endl;
}
return 0;
}

``````

Problem Link: CodeChef: Practical coding for everyone

@sbolt
The logic is if the sum upto n is even then print n else print n-1
now see this example :-
n=4
1 2 3 4 =10 which is even so answer is 4
n=5
1 2 3 4 5 =15 which is not even so i will leave 1 and sum up the rest which is 2 3 4 5 =14 which is even so n-1 will be my answer.

ok i get what i was missing. thanks. i was only removing the last number of the array, and not the first one.