My issue
why we have to perform this operation
int l=m%4;
if(l==0 && m!=0)
{
l=4;
}
My code
#include <stdio.h>
#include<math.h>
int main(void) {
// your code goes here
int t;
scanf("%d",&t);
while(t--){
long long int x,m,a,nn=0, v;
scanf("%lld%lld",&x,&m);
for(int i=x;i>0;i/=10){
a=i%10;
int l=m%4;
if(l==0 && m!=0)
{
l=4;
}
v=pow(a,l);
if(v<10)
nn=nn*10+v;
else
{
nn=nn*10+(v%10);
}
}
if(nn%7==0)
printf("YES\n");
else
printf("NO\n");
}
return 0;
}
Problem Link: CodeChef: Practical coding for everyone