Help me in solving SLOWSOLN problem

My issue

why are we using sumN/maxN and sumN%maxN ??

My code

#include <iostream>
using namespace std;
int main() {
	// your code goes here
	int t;
	cin>>t;
	while(t--)
	{
	    long int maxT,maxN,sumN;
	    int i;
	    cin>>maxT>>maxN>>sumN;
	    maxT*sumN*sumN
	    cout<<endl;
	}
	return 0;
}

Problem Link: SLOWSOLN Problem - CodeChef

@satyam301
We used sumN/maxN to get the number of test cases used.
and sumN%maxN to get the value of N in the last test case.