### My issue

i dont understand why this code would give wrong answer.

For a string of length n, to have equal occurrences of 01 and 10, we can make sure the string 010 exists in the string spaced with 0s.

hence for n=6, it would be 010010 (as 6 is a multiple of 3 the string 010 repeats twice) for n = 7 it would be 0100100 there would be an extra 0 at the end as 7%3 = 1.

i don’t get for which case this approach would fail

### My code

```
#include <iostream>
using namespace std;
int main() {
// your code goes here
int t; cin>>t ;
while(t--){
int n ; cin>>n ;
if(n%3 == 0 ){
for(int i = 0; i<n/3; i++){
cout<<"010" ;
}
cout<<endl ;
break ;
}else if(n%3 == 1){
for(int i = 0; i<n/3; i++){
cout<<"010" ;
}
cout<<"0"<<endl ;
}else if(n%3 == 2){
for(int i = 0; i<n/3; i++){
cout<<"010" ;
}
cout<<"00"<<endl;
}
}
return 0;
}
```

Problem Link: ZOOZ Problem - CodeChef