Help Plzz.Why wrong answer

general
, ,
1

#include<stdio.h>

int main()

{

int i,n,a[10000],b[10000],c[10000],e[10000],max1=0,max2=0,m=0,k=0;

scanf("%d\n",&n);

for(i=0;i<n;i++)

{

scanf("%d %d",&a[i],&b[i]);

if(a[i]>b[i])
{
    c[m]=a[i]-b[i];
    m++;

}
if(b[i]>a[i])
{
    e[k]=b[i]-a[i];
    k++;
}

}

max1=c[0];

max2=e[0];

for(i=0;i<n-1;i++)

{

if(c[i+1]>c[i])

{

    max1=c[i+1];

}

if(e[i+1]>e[i])

{

    max2=e[i+1];

}

}

if(max1>max2)

{

printf("%d %d",1,max1);

}

else if(max2>max1)

{

printf("%d %d",2,max2);

}

return 0;

}

2

@itsayushbansal You are incrementing the value of m and k so its not for sure that both get the same values. Plus your loop from 0 to n-1 is wrong because arrays c and e do not even contain as many elements, they have elements equal to m and k respectively. Change that. Plus use “\n” while printing the result.

3

Can you please post link to the problem?

1 Like
4

http://www.codechef.com/viewsolution/5130174

5

if max1 and max2 are same then there will not be any value to print…
and also same mistake in scaning for loop if a[i] and b[i] are same…

6

it is given in ques to avoid tie cases

1 Like