Help with May Lunchtime Division 2 (2019) REMMAX

help
1

I wrote the code for the problem CodeChef: Practical coding for everyone

I cant seem to understand why I am getting an error. Please help me. My code is as follows:-

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int t;
    cin>>t;
    while(t--)
    {
        string s;
        cin>>s;
        int n=s.length();
        bool flag=false;
        if(n==1)
        {
            cout<<s<<endl;
            continue;
        }
        if(s[0]=='1')
        {
            flag=true;
        }
        else if(s[1]!='9')
        {
            s[0]=s[0]-1;
        }
        for(int i=1;i<n;i++)
        {
            if(flag==false)
            {
                s[i]='9';
            }
            else
            {
                if(s[i]!='0'&&i!=n-1&&s[i+1]!='9')
                {
                    s[i]=s[i]-1;
                    flag=false;
                }
            }
        }
        cout<<s<<endl;
    }
}
2

your code is not indented
you did not even explain what prob you are facing
How and Why one shld help you !

Still i will try
This prob has many edge cases
What i suggest is take any working prob and try all numbers from 1 to 5000 and see you get correct ans for them
No need to enter numbers manually. You can make a text file for it

3

hi
sorry !
my bad…I edited my question and pasted the corrected code and in that I did not notice i erased my explanation

4

did u understand the approach i told u ?
in that way you can debug ur code
its really difficult to spot mistakes in someone else’s code in such kind prob which has so many edge cases

5

Yes! Let me try that. Thanks

6

as @ganesh92 said you can calculate answer for n =1 to 10000 , by making a function reverse which reverses each number and returns it … and then arr[n]=max(arr[n-1],reverse(i))…arr[1]=1…now reverse (arr[n]) is your answer for n = 1 to 10000 …This will give correct answer for the subtask

1 Like