https://www.codechef.com/MCL12021/problems/MCLP1102

PROBLEM LINK: Contest Page | CodeChef

Author: Setter’s name

Tester: Tester’s name

Editorialist: Editorialist’s name

DIFFICULTY : EASY

PREREQUISITES:

Nill

PROBLEM:

Hermione Granger has been working on a new spell which she picked up from the library. This is how the spell works: it completely reverses whatever number she wants. Guide Hermione through this.

QUICK EXPLANATION:

The individual digits are obtained and the positions are reversed

EXPLANATION:

This program takes an integer input from the user. Then the while loop is used until n != 0 is false (0).

In each iteration of the loop, the remainder when n is divided by 10 is calculated and the value of n is reduced by 10 times.

Inside the loop, the reversed number is computed using:

reversedNumber = reversedNumber*10 + remainder

SOLUTIONS:

Setter's Solution

#include

using namespace std;

int main() {

int n, reversedNumber = 0, remainder;

cin >> n;

while(n != 0) {

remainder = n%10;

reversedNumber = reversedNumber*10 + remainder;

n /= 10;

}

cout << reversedNumber;

return 0;

}

Tester's Solution

Same Person

Editorialist's Solution

Same Person