Increment operator behaviour

general
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1

Today i came across a code which i am not able to understand.It would be great if someone could explain the output and behaviour of the code.

  i=1;
ans=i++ + ++i;

Now output of this code is 4.
I understand that increment operators have right to left associativity.

Now consider this code

i=1;
ans=i++ * ++i;

output of this code is 3.
How? Why does it behave differently in these situations.Can someone please elaborate and explain how to both of the expressions evaluate???

2

Let’s analyse the case 1

first i=1
ans=i++ (after this ans=1,i=2) as i++ first takes the current value of i for the current operation
and then increment it
ans=i++ + ++i(when you do ++i i becomes 3 from 2) as ++i first increment i and then take the incremented value of i for operation so
ans=1+3, this gives ans=4

Now for 2nd case

i=1
ans=i++ (ans=1,i=2) same as before
ans=i++ * ++i (i was 2 now becomes 3) same as before
so ans=1*3, this gives ans=3

4

Wait, I couln’t identify the problem.

i++ --> 1; i is now 2

++i --> 3; i is now 3

ans = 1 * 3 = 3

5

okay i understand now, i read in C by dennis Rithcie that associativity of ++ is from right to left so i thought it would increment from right to left, so i was confused