PROBLEM LINK:
Setter: abhi_inav
Testers: tejas10p, rivalq
Editorialist: kiran8268
DIFFICULTY:
475
PREREQUISITES:
None
PROBLEM:
Given the maximum rebatable amount X and the amount for repairing as Y, our objective is to determine the amount that will be rebated by the insurance company.
EXPLANATION:
There are only two cases :
a. The amount for repairing , Y \le X. Then the amount rebated by the insurance company will be Y.
b. The amount for repairing , Y > X. Then the amount rebated by the insurance company will be X.
TIME COMPLEXITY:
Time complexity is O(1).
SOLUTION:
Editorialist's Solution
int t;
cin>>t;
while(t--)
{
int x,y;
cin >> x >> y;
if(y <= x) cout << y << endl;
else cout << x << endl;
}