# PROBLEM LINK:

**Setter:** abhi_inav

**Testers:** tejas10p, rivalq

**Editorialist:** kiran8268

# DIFFICULTY:

475

# PREREQUISITES:

None

# PROBLEM:

Given the maximum rebatable amount X and the amount for repairing as Y, our objective is to determine the amount that will be rebated by the insurance company.

# EXPLANATION:

There are only two cases :

a. The amount for repairing , Y \le X. Then the amount rebated by the insurance company will be Y.

b. The amount for repairing , Y > X. Then the amount rebated by the insurance company will be X.

# TIME COMPLEXITY:

Time complexity is O(1).

# SOLUTION:

## Editorialist's Solution

```
int t;
cin>>t;
while(t--)
{
int x,y;
cin >> x >> y;
if(y <= x) cout << y << endl;
else cout << x << endl;
}
```