daveo
June 17, 2014, 4:28pm
1
Hi im new to codechef and just wanted to know why this solution is not being accepted even though it gives me the correct output on codeblocks. I read the faqs and even those didnt help. Please see, thanks
#include
using namespace std;
int main()
{ int i, x[10];
for(i=0;i<4;i++)
{
if (x[i]==42)
break;
else if(x[i]>=100)
break;
else if (x[i]<0)
break;
else
cout<<x[i]<<"\n";
}
}
from where are you taking inputs?? you should use cin or scanf to take input …
3 Likes
Go to this link: getting-started (this is link for codechef getting started on the main page of codechef)
On the link above : go to Solving your first problem in C++, which contains a video.
The video should help, if you still get wrong answer, you can comment below in the comment section.
Also, read the FAQ carefully : FAQ
3 Likes
daveo
June 17, 2014, 4:50pm
4
#include
using namespace std;
int main()
{ int i, x[10];
for(i=0;i<4;i++)
{cin>>x[i];}
for(i=0;i<4;i++)
{
if (x[i]==42)
break;
else if(x[i]>=100)
break;
else if (x[i]<0)
break;
else
cout<<x[i]<<"\n";
}
}
but even this is wrong
See, you are scanning only 4 numbers.It’s not mentioned that there are only 4 numbers.You need to scan upto the number scanned is 42.I think this may help you:
while(1)
{
scanf("%d",&x);
if(x==42)
{ break;
}
else
{printf("%d\n",x);
}
}
1 Like
CodeChef: Practical coding for everyone here is my code just take a look that how to take input …
Is it giving syntax error??
The questions asks you to get input from the console and you are not doing that…
1 Like
you need to take the input in the code
Why are you restricting your input to 4 times while the questions ask you to stop getting input when the number entered is 42