# PROBLEM LINK:

Practice

Contest: Division 1

Contest: Division 2

Contest: Division 3

Contest: Division 4

* Author:* notsoloud

*raysh_07*

**Tester:***iceknight1093*

**Editorialist:**# DIFFICULTY:

TBD

# PREREQUISITES:

None

# PROBLEM:

Given the population P and number of literate people L in Chefland, check if the literacy rate is at least 75\%.

# EXPLANATION:

As the statement mentions, the literacy rate is \frac{L}{P} \cdot 100 \%.

More specifically, the literacy rate is \geq 75\% if and only if \frac{L}{P} \geq 0.75, i.e, the proportion of people that are literate is at least 0.75.

So, simply use an `if`

condition to check whether \frac{L}{P} \geq 0.75 or not.

# TIME COMPLEXITY:

\mathcal{O}(1) per testcase.

# CODE:

## Editorialist's code (Python)

```
for _ in range(int(input())):
p, l = map(int, input().split())
print('Yes' if l/p >= 0.75 else 'No')
```