# PROBLEM LINK:

* Author:* Amruta Patil

*Amruta Patil*

**Tester:***Amruta Patil*

**Editorialist:**# DIFFICULTY:

EASY

# PREREQUISITES:

Basic Math

# PROBLEM:

In a Juice center there are some mangoes kept in a basket. The basket contains both small size mangoes and large size mangoes. If a juice seller wants to prepare a glass of juice he has to either use one large size mango or two small size mangoes. If a basket contains **M** large mangoes and **N** small size mangoes, how many glasses of mango juice can be prepared?

# QUICK EXPLANATION:

A juice center contains some mangoes, there are **M** large size mangoes and **N** small size mangoes. A glass of juice can be prepared either by one large size mango or two small size mangoes. Then, how many glass of juice can be prepared with **M** large size and **N** small size mangoes.

Consider for example, if there are **12** large size mangoes and **13** small size mangoes.

Then, total no of glasses of juice that can be prepared is **12+ 13/2 =18**.

# SOLUTIONS:

## Setter's Solution

```
#include <stdio.h>
int main()
{
int t,m,n,i;
scanf("%d",&t);
for(i=0;i<t;i++){
scanf("%d %d",&m,&n);
printf("%d\n", m+(n/2));
}
return 0;
}
```