MAXTASTE-EDITORIAL

editorial
,
1

PROBLEM LINK:

Contest
Practice

Setter: inov_360
Testers: iceknight1093 , jeevanjyot
Editorialist: kiran8268

DIFFICULTY:

627

PREREQUISITES:

None

PROBLEM:

Chef has four ingredients A, B, C and D with tastiness a, b, c, and d respectively. He can use either A or B as the first ingredient and either C or D as the second ingredient. The tastiness of a dish is the sum of tastiness of its ingredients. Find the maximum possible tastiness of the dish that the chef can prepare.

EXPLANATION:

Given, the testiness of the dish is the sum of the testiness of the ingredients. Also, out of 4 ingredients only two are used at a time. That is either A or B is used as the first ingredient and C or D is used as the second ingredient.
Thus the testiness of the dish is: Testiness of (A or B) + Testiness of (C or D).

Our objective is to find the maximum testiness, thus our desired output is:
Max(A or B) + Max (C or D).

TIME COMPLEXITY:

Time complexity is O(1).

SOLUTION:

Editorialist's Solution 
int t;
	cin>>t;
	while(t--)
	{
	    int a,b,c,d;
	    cin>>a>>b>>c>>d;
	    
	    cout<<max(a,b)+max(c,d)<<"\n";
	}
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