# PROBLEM LINK:

Practice

Contest: Division 1

Contest: Division 2

Contest: Division 3

Contest: Division 4

* Author:* Utkarsh Gupta

*Utkarsh Gupta, Jatin Garg*

**Testers:***Nishank Suresh*

**Editorialist:**# DIFFICULTY:

387

# PREREQUISITES:

None

# PROBLEM:

In a bus with 100 seats, a passenger will always choose to exit from the side closest to their seat. The left exit is beside seat 1 and the right exit is beside seat 100.

Which exit will a passenger at seat X choose?

# EXPLANATION

The left exit is closer to seats 1, 2, \ldots, 50, and the right exit is closer to the other seats.

So, the solution is to print “Left” if X \leq 50 and “Right” otherwise.

# TIME COMPLEXITY

\mathcal{O}(1) per test case.

# CODE:

## Editorialist's code (Python)

```
for _ in range(int(input())):
x = int(input())
print('Left' if x <= 50 else 'Right')
```